write a program to print the number of days in a given year.

examples:

input: 2023
output: 365
explanation: the year 2023 is not a leap year, therefore the number of days are 365.

input: 2024
output: 366
explanation: the year 2024 is a leap year, therefore the number of days are 366.

approach: to solve the problem, follow the below idea:

to determine the number of days in a given year, you need to consider whether the year is a leap year or not. a year is a leap year if the following conditions are satisfied:

the year is multiple of 400.
the year is a multiple of 4 and not a multiple of 100.
so, if it is a leap year the year contains 366 days and if not a leap year, then no. of days in a year are 365.

below is the implementation of the above approach:

c++

#include <iostream>
using namespace std;

bool isleapyear(int year)
{
    // leap year is divisible by 4, but not divisible by 100
    // unless divisible by 400
    return (year % 4 == 0 && year % 100 != 0)
        || (year % 400 == 0);
}

int main()
{
    int year = 2024;

    // check if the year is a leap year
    if (isleapyear(year)) {
        cout << "leap year. it has 366 days." << endl;
    }
    else {
        cout << "common year. it has 365 days." << endl;
    }

    return 0;
}

java

public class leapyearchecker {

    // function to check if a year is a leap year
    static boolean isleapyear(int year) {
        // leap year is divisible by 4, but not divisible by 100 unless divisible by 400
        return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
    }

    public static void main(string[] args) {
        // set the year to be checked
        int year = 2024;

        // check if the year is a leap year
        if (isleapyear(year)) {
            system.out.println("leap year. it has 366 days.");
        } else {
            system.out.println("common year. it has 365 days.");
        }
    }
}

python3

def is_leap_year(year):
    # leap year is divisible by 4, but not divisible by 100
    # unless divisible by 400
    return (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0)

if __name__ == "__main__":
    year = 2024

    # check if the year is a leap year
    if is_leap_year(year):
        print(f"leap year. it has 366 days.")
    else:
        print(f"common year. it has 365 days.")

using system;

class leapyearcheck
{
    // function to check if a year is a leap year
    static bool isleapyear(int year)
    {
        // leap year is divisible by 4, but not divisible by 100
        // unless divisible by 400
        return (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);
    }

    static void main()
    {
        int year = 2024;

        // check if the year is a leap year
        if (isleapyear(year))
        {
            console.writeline("leap year. it has 366 days.");
        }
        else
        {
            console.writeline("common year. it has 365 days.");
        }
    }
}

javascript

// function to check if a year is a leap year
function is_leap_year(year) {
    // leap year is divisible by 4, but not divisible by 100 unless divisible by 400
    return (year % 4 === 0 && year % 100 !== 0) || (year % 400 === 0);
}

// main program
const year = 2024;

// check if the year is a leap year
if (is_leap_year(year)) {
    console.log(`leap year. it has 366 days.`);
} else {
    console.log(`common year. it has 365 days.`);
}

output

leap year. it has 366 days.

time complexity: o(1)
auxiliary space: o(1)

comment

article tags:

android

programming

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